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Paper Set
2022

2022 AMC10 Paper & Solutions Pick Paper A

First in-person exam since pandemic, 25 solutions. Number theory features Chinese Remainder Theorem variant.

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25 Questions
40 Minutes
Max Score 25
No Calculator
Exam Overview

Exam Overview

This exam emphasizes number theory. Overall difficulty is moderate.

DDifficulty

  • EasyQ1-10
  • MediumQ11-20
  • HardQ21-25

TTopics

  • Algebra35%
  • Geometry30%
  • Number Theory20%
  • Combinatorics15%

AAwards

AIME Qualification
AIME Qualification (Top 2.5%)
112+
Honor Roll
Honor Roll (Top 5%)
99+
Achievement Roll
Grade 6 and below · 15+ points
89+
Sample Problems

2022 AMC10 Sample Problems (12 questions)

Sample reference problems by difficulty — click an option to check your answer

Q1EasyPolynomial
If f(x) = 2x² - 5x + 2, find f(4).
A) 10
B) 12
C) 14
D) 16
E) 18

Steps

1f(4) = 2×4² - 5×4 + 2
2= 2×16 - 20 + 2 = 14
Answer: CSubstitute, then exponentiate, multiply/divide, add/subtract
Q3EasyArithmetic Seq
Arithmetic sequence: a₁=5, d=4, find the 14-th term.
A) 45
B) 51
C) 63
D) 57
E) 69

Steps

1aₙ = a₁ + (n-1)d
2a_14 = 5 + 13×4 = 57
Answer: DGeneral term: aₙ=a₁+(n-1)d
Q5EasyExponent
If 3ˣ = 243, find x.
A) 3
B) 4
C) 6
D) 7
E) 5

Steps

1243 = 3^5
2so x = 5
Answer: EConvert to same base, compare exponents
Q7EasyVieta's
Sum of roots of x² - 7x + 6 = 0?
A) 7
B) 3
C) 5
D) 9
E) 11

Steps

1Vieta's:sum of roots = -(-7)/1 = 7
2product of roots = 6
Answer: AFor x²-px+q=0, sum of roots = p
Q10MediumDivisibility
How many integers from 1 to 32 are divisible by 4?
A) 4
B) 8
C) 6
D) 10
E) 12

Steps

1⌊32 / 4⌋ = 8
Answer: BCount divisible by k: ⌊n/k⌋
Q12MediumDiagonals
How many diagonals does a regular 11-gon have?
A) 38
B) 41
C) 44
D) 47
E) 50

Steps

1diagonals = n(n-3)/2
2= 11×8/2 = 44
Answer: Cn-gon diagonals: n(n-3)/2
Q15MediumCombination
Compute C(8, 3).
A) 44
B) 50
C) 62
D) 56
E) 68

Steps

1C(n,3) = n(n-1)(n-2)/6
2= 8×7×6/6 = 56
Answer: DCombination: C(n,k)=n!/(k!(n-k)!)
Q17MediumPythagorean
Right triangle legs 6 and 8, find the hypotenuse.
A) 6
B) 8
C) 12
D) 14
E) 10

Steps

1c² = 6² + 8² = 36 + 64 = 100
2c = √100 = 10
Answer: EPythagorean theorem a²+b²=c²
Q20HardModular Arith
Find the remainder of 5^5 divided by 7.
A) 3
B) 1
C) 2
D) 4
E) 5

Steps

1compute 5^5 mod 7
2simplify step by step (modular arithmetic)
3=3
Answer: AModular arithmetic simplifies large exponents
Q22HardCompleting Sq
Find the minimum of f(x) = x² - 8x + 20.
A) 0
B) 4
C) 2
D) 6
E) 8

Steps

1complete the square:f(x) = (x - 4)² + 4
2when x = 4 , min at 4
Answer: BCompleting the square for quadratic extrema
Q24HardInclusion-Excl
5 distinct balls into 3 distinct boxes, each ≥1 ball, how many ways?
A) 118
B) 134
C) 150
D) 166
E) 182

Steps

1total 3^5 = 243
2subtract empty boxes: -C(3,1)×2^5 = -96
3add back 2 empty boxes: +C(3,2)×1 = +3
4total 243 - 96 + 3 = 150
Answer: CInclusion-exclusion handles 'at least'
Q25HardLaw of Cosines
In △ABC, a=6, b=7, cos C=1/2, find c².
A) 33
B) 38
C) 48
D) 43
E) 53

Steps

1Law of cosines c² = a² + b² - 2ab·cos C
2= 36 + 49 - 42 = 43
Answer: DLaw of cosines is key for solving triangles
Q1EasyPolynomial
If f(x) = 2x² - 7x + 2, find f(4).
A) 2
B) 4
C) 6
D) 8
E) 10

Steps

1f(4) = 2×4² - 7×4 + 2
2= 2×16 - 28 + 2 = 6
Answer: CSubstitute, then exponentiate, multiply/divide, add/subtract
Q3EasyArithmetic Seq
Arithmetic sequence: a₁=7, d=4, find the 14-th term.
A) 47
B) 53
C) 65
D) 59
E) 71

Steps

1aₙ = a₁ + (n-1)d
2a_14 = 7 + 13×4 = 59
Answer: DGeneral term: aₙ=a₁+(n-1)d
Q5EasyExponent
If 3ˣ = 243, find x.
A) 3
B) 4
C) 6
D) 7
E) 5

Steps

1243 = 3^5
2so x = 5
Answer: EConvert to same base, compare exponents
Q7EasyVieta's
Sum of roots of x² - 9x + 6 = 0?
A) 9
B) 5
C) 7
D) 11
E) 13

Steps

1Vieta's:sum of roots = -(-9)/1 = 9
2product of roots = 6
Answer: AFor x²-px+q=0, sum of roots = p
Q10MediumDivisibility
How many integers from 1 to 34 are divisible by 4?
A) 4
B) 8
C) 6
D) 10
E) 12

Steps

1⌊34 / 4⌋ = 8
Answer: BCount divisible by k: ⌊n/k⌋
Q12MediumDiagonals
How many diagonals does a regular 13-gon have?
A) 59
B) 62
C) 65
D) 68
E) 71

Steps

1diagonals = n(n-3)/2
2= 13×10/2 = 65
Answer: Cn-gon diagonals: n(n-3)/2
Q15MediumCombination
Compute C(10, 3).
A) 94
B) 107
C) 133
D) 120
E) 146

Steps

1C(n,3) = n(n-1)(n-2)/6
2= 10×9×8/6 = 120
Answer: DCombination: C(n,k)=n!/(k!(n-k)!)
Q17MediumPythagorean
Right triangle legs 7 and 24, find the hypotenuse.
A) 21
B) 23
C) 27
D) 29
E) 25

Steps

1c² = 7² + 24² = 49 + 576 = 625
2c = √625 = 25
Answer: EPythagorean theorem a²+b²=c²
Q20HardModular Arith
Find the remainder of 5^5 divided by 7.
A) 3
B) 1
C) 2
D) 4
E) 5

Steps

1compute 5^5 mod 7
2simplify step by step (modular arithmetic)
3=3
Answer: AModular arithmetic simplifies large exponents
Q22HardCompleting Sq
Find the minimum of f(x) = x² - 8x + 22.
A) 2
B) 6
C) 4
D) 8
E) 10

Steps

1complete the square:f(x) = (x - 4)² + 6
2when x = 4 , min at 6
Answer: BCompleting the square for quadratic extrema
Q24HardInclusion-Excl
5 distinct balls into 3 distinct boxes, each ≥1 ball, how many ways?
A) 118
B) 134
C) 150
D) 166
E) 182

Steps

1total 3^5 = 243
2subtract empty boxes: -C(3,1)×2^5 = -96
3add back 2 empty boxes: +C(3,2)×1 = +3
4total 243 - 96 + 3 = 150
Answer: CInclusion-exclusion handles 'at least'
Q25HardLaw of Cosines
In △ABC, a=8, b=7, cos C=1/2, find c².
A) 45
B) 51
C) 63
D) 57
E) 69

Steps

1Law of cosines c² = a² + b² - 2ab·cos C
2= 64 + 49 - 56 = 57
Answer: DLaw of cosines is key for solving triangles

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