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Paper Set
2019

2019 AMC10 Paper & Solutions Pick Paper A

25 complete solutions, algebra focuses on equation applications, geometry covers circle properties. Combinatorics introduces recursion.

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25 Questions
40 Minutes
Max Score 25
No Calculator
Exam Overview

Exam Overview

This exam emphasizes algebra, combinatorics, equations. Overall difficulty is moderate.

DDifficulty

  • EasyQ1-10
  • MediumQ11-20
  • HardQ21-25

TTopics

  • Algebra35%
  • Geometry30%
  • Number Theory15%
  • Combinatorics20%

AAwards

AIME Qualification
AIME Qualification (Top 2.5%)
109+
Honor Roll
Honor Roll (Top 5%)
96+
Achievement Roll
Grade 6 and below · 15+ points
89+
Sample Problems

2019 AMC10 Sample Problems (12 questions)

Sample reference problems by difficulty — click an option to check your answer

Q1EasyPolynomial
If f(x) = 2x² - 7x + 2, find f(5).
A) 11
B) 14
C) 20
D) 23
E) 17

Steps

1f(5) = 2×5² - 7×5 + 2
2= 2×25 - 35 + 2 = 17
Answer: ESubstitute, then exponentiate, multiply/divide, add/subtract
Q3EasyArithmetic Seq
Arithmetic sequence: a₁=6, d=6, find the 11-th term.
A) 66
B) 52
C) 59
D) 73
E) 80

Steps

1aₙ = a₁ + (n-1)d
2a_11 = 6 + 10×6 = 66
Answer: AGeneral term: aₙ=a₁+(n-1)d
Q5EasyExponent
If 3ˣ = 729, find x.
A) 4
B) 6
C) 5
D) 7
E) 8

Steps

1729 = 3^6
2so x = 6
Answer: BConvert to same base, compare exponents
Q7EasyVieta's
Sum of roots of x² - 9x + 7 = 0?
A) 5
B) 7
C) 9
D) 11
E) 13

Steps

1Vieta's:sum of roots = -(-9)/1 = 9
2product of roots = 7
Answer: CFor x²-px+q=0, sum of roots = p
Q10MediumDivisibility
How many integers from 1 to 49 are divisible by 4?
A) 8
B) 10
C) 14
D) 12
E) 16

Steps

1⌊49 / 4⌋ = 12
Answer: DCount divisible by k: ⌊n/k⌋
Q12MediumDiagonals
How many diagonals does a regular 8-gon have?
A) 14
B) 17
C) 23
D) 26
E) 20

Steps

1diagonals = n(n-3)/2
2= 8×5/2 = 20
Answer: En-gon diagonals: n(n-3)/2
Q15MediumCombination
Compute C(10, 3).
A) 120
B) 94
C) 107
D) 133
E) 146

Steps

1C(n,3) = n(n-1)(n-2)/6
2= 10×9×8/6 = 120
Answer: ACombination: C(n,k)=n!/(k!(n-k)!)
Q17MediumPythagorean
Right triangle legs 7 and 24, find the hypotenuse.
A) 21
B) 25
C) 23
D) 27
E) 29

Steps

1c² = 7² + 24² = 49 + 576 = 625
2c = √625 = 25
Answer: BPythagorean theorem a²+b²=c²
Q20HardModular Arith
Find the remainder of 6^5 divided by 8.
A) 1
B) 2
C) 0
D) 3
E) 4

Steps

1compute 6^5 mod 8
2simplify step by step (modular arithmetic)
3=0
Answer: CModular arithmetic simplifies large exponents
Q22HardCompleting Sq
Find the minimum of f(x) = x² - 10x + 29.
A) 0
B) 2
C) 6
D) 4
E) 8

Steps

1complete the square:f(x) = (x - 5)² + 4
2when x = 5 , min at 4
Answer: DCompleting the square for quadratic extrema
Q24HardInclusion-Excl
5 distinct balls into 3 distinct boxes, each ≥1 ball, how many ways?
A) 118
B) 134
C) 166
D) 182
E) 150

Steps

1total 3^5 = 243
2subtract empty boxes: -C(3,1)×2^5 = -96
3add back 2 empty boxes: +C(3,2)×1 = +3
4total 243 - 96 + 3 = 150
Answer: EInclusion-exclusion handles 'at least'
Q25HardLaw of Cosines
In △ABC, a=6, b=7, cos C=1/2, find c².
A) 43
B) 33
C) 38
D) 48
E) 53

Steps

1Law of cosines c² = a² + b² - 2ab·cos C
2= 36 + 49 - 42 = 43
Answer: ALaw of cosines is key for solving triangles
Q1EasyPolynomial
If f(x) = 2x² - 9x + 2, find f(5).
A) 3
B) 5
C) 9
D) 11
E) 7

Steps

1f(5) = 2×5² - 9×5 + 2
2= 2×25 - 45 + 2 = 7
Answer: ESubstitute, then exponentiate, multiply/divide, add/subtract
Q3EasyArithmetic Seq
Arithmetic sequence: a₁=8, d=6, find the 11-th term.
A) 68
B) 54
C) 61
D) 75
E) 82

Steps

1aₙ = a₁ + (n-1)d
2a_11 = 8 + 10×6 = 68
Answer: AGeneral term: aₙ=a₁+(n-1)d
Q5EasyExponent
If 3ˣ = 729, find x.
A) 4
B) 6
C) 5
D) 7
E) 8

Steps

1729 = 3^6
2so x = 6
Answer: BConvert to same base, compare exponents
Q7EasyVieta's
Sum of roots of x² - 11x + 7 = 0?
A) 7
B) 9
C) 11
D) 13
E) 15

Steps

1Vieta's:sum of roots = -(-11)/1 = 11
2product of roots = 7
Answer: CFor x²-px+q=0, sum of roots = p
Q10MediumDivisibility
How many integers from 1 to 51 are divisible by 4?
A) 8
B) 10
C) 14
D) 12
E) 16

Steps

1⌊51 / 4⌋ = 12
Answer: DCount divisible by k: ⌊n/k⌋
Q12MediumDiagonals
How many diagonals does a regular 10-gon have?
A) 29
B) 32
C) 38
D) 41
E) 35

Steps

1diagonals = n(n-3)/2
2= 10×7/2 = 35
Answer: En-gon diagonals: n(n-3)/2
Q15MediumCombination
Compute C(12, 3).
A) 220
B) 174
C) 197
D) 243
E) 266

Steps

1C(n,3) = n(n-1)(n-2)/6
2= 12×11×10/6 = 220
Answer: ACombination: C(n,k)=n!/(k!(n-k)!)
Q17MediumPythagorean
Right triangle legs 5 and 12, find the hypotenuse.
A) 9
B) 13
C) 11
D) 15
E) 17

Steps

1c² = 5² + 12² = 25 + 144 = 169
2c = √169 = 13
Answer: BPythagorean theorem a²+b²=c²
Q20HardModular Arith
Find the remainder of 6^5 divided by 8.
A) 1
B) 2
C) 0
D) 3
E) 4

Steps

1compute 6^5 mod 8
2simplify step by step (modular arithmetic)
3=0
Answer: CModular arithmetic simplifies large exponents
Q22HardCompleting Sq
Find the minimum of f(x) = x² - 10x + 31.
A) 2
B) 4
C) 8
D) 6
E) 10

Steps

1complete the square:f(x) = (x - 5)² + 6
2when x = 5 , min at 6
Answer: DCompleting the square for quadratic extrema
Q24HardInclusion-Excl
5 distinct balls into 3 distinct boxes, each ≥1 ball, how many ways?
A) 118
B) 134
C) 166
D) 182
E) 150

Steps

1total 3^5 = 243
2subtract empty boxes: -C(3,1)×2^5 = -96
3add back 2 empty boxes: +C(3,2)×1 = +3
4total 243 - 96 + 3 = 150
Answer: EInclusion-exclusion handles 'at least'
Q25HardLaw of Cosines
In △ABC, a=8, b=7, cos C=1/2, find c².
A) 57
B) 45
C) 51
D) 63
E) 69

Steps

1Law of cosines c² = a² + b² - 2ab·cos C
2= 64 + 49 - 56 = 57
Answer: ALaw of cosines is key for solving triangles

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